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11x^2-3x-180=0
a = 11; b = -3; c = -180;
Δ = b2-4ac
Δ = -32-4·11·(-180)
Δ = 7929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7929}=\sqrt{9*881}=\sqrt{9}*\sqrt{881}=3\sqrt{881}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{881}}{2*11}=\frac{3-3\sqrt{881}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{881}}{2*11}=\frac{3+3\sqrt{881}}{22} $
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